How do you simplify #(35a^14 b^6) /( -7a^7 b^3)#?

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Answer 1 · 2016-01-15T13:15:10

#- (35a^7b^3)/7#

To aid understanding I am splitting the fraction into its component parts:

Given: #(35a^14b^6)/(-7a^7b^3)#

Rewrite as: # -35/7xx(a^14)/(a^7) xx (b^6)/(b^3)#

#-35/7xxa^(14-7)xxb^(6-3)#

#-35/7xx a^7xxb^3#

7 is a prime number so it will not divide into 35 'without giving a remainder'. So leave it as it.

Writing the solution in the same form as the question gives

#- (35a^7b^3)/7#