Question

How do you find the center, vertices, foci and asymptotes of `x^2-y^2=100`?

Answer 1

It can be recognized as the equation for a circle as it follows the general form `(x-h)^2 +(y-k)^2 = r^2`

Explanation:

This equation `x^2 +y^2 = 100` can be rewritten as
`(x-0)^2 +(y - 0)^2 =10^2`

It can be recognized as the equation for a circle as it follows the general form `(x-h)^2 +(y-k)^2 = r^2` where `(h,k)` is the center and `r` is the radius.

Therefore it does not have vertices, foci or asymptotes.

The center is `(0,0)` and the radius is `10`