Question

How much work would it take to push a `2 kg` weight up a `1 m` plane that is at an incline of `(5pi) / 12`?

Answer 1

The work needed is given by the formula `W = F*S*Sin(theta)`
here
`s = 1m`
`m=2kg`
`F= m.g` where `g=9.8 m/sec^2`

`W= m.g.s sin theta`
`W= (2) (9.8 ) (1) sin ( (5pi)/12)`
`W= 18.93 J`