How do you find all the real and complex roots of $x^{2} - 2 x + 1 = 0$ $x^2 - 2x +1 = 0$ ?

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Answer 1 · 2016-01-18T03:36:36

$x = 1$ $x=1$

This polynomial is a perfect square. It factors into

${(x - 1)}^{2} = 0$ $(x-1)^2=0$

Solve the equation by taking the square root of both sides.

$x - 1 = 0$ $x-1=0$

$x = 1$ $x=1$

This is the equation's only root. It has a multiplicity of $2$ $2$ .

How do you find all the real and complex roots of x2−2x+1=0x^2 - 2x +1 = 0?