How do you convert $y= x -4xy+y^2$ into a polar equation?

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Answer 1 · 2016-01-19T12:30:45

To convert to polar you need the following:

$y=rsin theta$
$x=rcos theta$
$r^2=x^2+y^2$
$theta = tan^-1(y/x)$

$rsintheta = rcostheta-r^2costhetasintheta+r^2sintheta$

Simplify and voila... Goodluck

How do you convert y= x -4xy+y^2 y= x -4xy+y^2 into a polar equation?