How do you find the LCD for $x - 4, x + 2$ $x-4 , x+2$ ?

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Answer 1 · 2016-01-20T07:13:52

The LCD of $(x - 4)$ $(x-4)$ and $(x + 2)$ $(x+2)$ as rational expressions is $1$ $1$ .

LCD is Least Common Divisor.

$(x - 4)$ $(x-4)$ and $(x + 2)$ $(x+2)$ can be thought of as rational expressions with divisor $1$ $1$ .

$(x - 4) = \frac{x - 4}{1}$ $(x-4) = (x-4)/1$ and $(x + 2) = \frac{x + 2}{1}$ $(x+2) = (x+2)/1$

Then the only common divisor (scalar or polynomial) they have is $1$ $1$ .

If you meant to ask what is the LCD of two rational expressions with denominators $(x - 4)$ $(x-4)$ and $(x + 2)$ $(x+2)$ then the answer is:

$(x - 4) (x + 2) = x^{2} - 2 x - 8$ $(x-4)(x+2) = x^2-2x-8$

The LCD in this case is the LCM (Least Common Multiple) of the two divisors.

How do you find the LCD for x-4 , x+2x−4,x+2x-4 , x+2?