Question

How do you find the instantaneous rate of change of the function `d=200t * 2^(-t)` when t=1?

Answer 1

I found: `30.7`

Explanation:

We need to evaluate the derivative with respect to `t` and evaluate it at `t=1`:

`d'(t)=200/2^t-200t*ln(2)/2^t=200/2^t[1-tln(2)]`

Evaluate it at `t=1`

`d'(1)=200/2^1[1-1*ln(2)]=30.7`