How do you write the equation of the circle with center at (5,-3) and radius of 4?

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Answer 1 · 2016-01-22T15:21:02

#(x-5)^2+(y+3)^2=16#

The standard form of the equation for a circle with a center at #(h,k)# and radius #r# is

#(x-h)^2+(y-k)^2=r^2#

From the information provided, we know that #h=5,k=-3,# and #r=4#, hence the equation

#(x-5)^2+(y-(-3))^2=4^2#

Which yields, when simplified

#(x-5)^2+(y+3)^2=16#

Graphed:

graph{((x-5)^2+(y+3)^2-16)((x-5)^2+(y+3)^2-.02)=0 [-7.45, 15.07, -8.27, 2.98]}