What is the polar form of #( -7,1 )#?

1 Answer
Jan 22, 2016

# (5sqrt2 , 3 )#

Explanation:

Use the following formulae linking Cartesian to Polar coordinates.

# • r^2 = x^2 + y^2 #

# • theta = tan^-1 (y/x ) #

[( - 7 , 1 ) is a point in the 2nd quadrant and care must be taken

to ensure that # theta# , is in the 2nd quadrant.]

so # r^2 = (-7)^2 + 1^2 = 49 + 1 = 50 rArr r =sqrt50 = 5sqrt2 #

and #theta = tan^-1 =(1/-7 ) = - 0.14color(black)("radians") #

#rArr theta = ( pi - 0.14 ) = 3 color(black)("radians" ) #