Question

How do you solve `2/3 x^2 + 1/4 x= 3`?

Answer 1

`x=(-3+-3sqrt(129))/16`

Explanation:

First simplify `2/3x^2+1/4x=3` by multiplying everything by `12` to clear the fractions:

`8x^2+3x=36`

Re-write in standard `ax^2+bx+c=0` form
`8x^2+3x-36=0`

Apply the quadratic formula `x=(-b+-sqrt(b^2-4ac))/(2a)` to obtain the roots.

`x=(-3+-sqrt(9-4(8)(-36)))/(2(8))`

Simplify
`x=-(3+-3sqrt(129))/16`