Question

What is the speed of an object that travels from `( 1, -2, 3 )` to `( -5, 6, 7 )` over `4 s`?

Answer 1

`2.693m//s`

Explanation:

The distance between the 2 given 3-dimensional points may be found from the normal Euclidean metric in `RR^3` as follows :

`x=d( (1,-2,3);(-5,6,7) )=sqrt((1-(-5))^2+(-2-6)^2+(3-7)^2)`

`=sqrt(36+64+16`

`=sqrt116m` , (Assuming the SI units are used)

Therefore the speed of the object by definition would be the rate of change in distance and given by

`v=x/t=sqrt116/4=2.693m//s`.