Question

How would you graph a circle with the equation `(x+4)^2+(y-2)^2=9`?

Answer 1

This a circle centered at a point P(-4, 2) with a radius of 3.
So either enter the equation as is or get a compass out, locate
the center in graph paper, set the compass to 3 cm and draw.

Explanation:

graph{(x+4)^2 + (y-2)^2 = 9 [-9.2, 4.124, -1.12, 5.454]}