How do you find the inverse of $f(x) = log 2^x$ ?

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Answer 1 · 2016-01-26T06:09:18

$f^-1x=x/log2$

If a given equation is $f(x)=y$ then the inverse of that function is $f^-1(y)=x$

Now, given $f(x)=log2^x\impliesy=log2^x$

I'm sure you know this general log formula $log_nm^l=llog_nm$
So applying this the the equation above, $y=xlog2$

So that means $y/log2=x$ and fora fact, we know that $f^-1(y)=x$ , so $f^-1y=y/log2$

Just replace $y$ with $x$ to get the general formula

How do you find the inverse of f(x) = log 2^xf(x) = log 2^x?