How do you balance #LiAl(OH)_4 + H_2O -> LiOH + Al(OH)_3 + H_2O#?
2 Answers
It's already balanced. Here, let's see what happens when we check what's on each side.
#"LiAl"("OH")_4 + cancel("H"_2"O") -> "LiOH" + "Al"("OH")_3 + cancel("H"_2"O")#
#color(green)("Li")color(highlight)("Al")color(blue)(("OH")_4) -> color(green)("Li")color(blue)("OH") + color(highlight)("Al")color(blue)(("OH")_3)#
Yep, it's fine the way it is. One lithium on each side, one aluminum on each side, and four
As for the charges,
Do you mean the reaction of lithium tetrahydroaluminate (
Explanation:
Lithium tetrahydroaluminate is an important hydride transfer reagent, and a very common reductant in organic chemistry. The reduction reaction is performed in THF (