Question

How do you find the derivative of `(x^2-3x+5)/x`?

Answer 1

`1-5/x^2`

Explanation:

`frac{d}{dx}(frac{x^2 - 3x + 5}{x}) = frac{d}{dx}(x - 3 + 5/x)`

`= 1 - 0 - 5/x^2`