How do you simplify #12-15 sqrt 6+8 sqrt 6-10 sqrt 36#?

1 Answer
Noah G
Jan 28, 2016

When adding/subtracting radicals, the numbers under the radical sign (#sqrt,root(3),root(4), etc#), must be equal.

Explanation:

12 - 15#sqrt(6)# + 8#sqrt(6) - 10(6)

We can now combine the constant terms (12 and 60) and the #sqrt(6)# terms.

12 - 60 + (-15 + 8)#sqrt(6)#

-48 - 7#sqrt(6)#

The answer is -48 - 7#sqrt(6)#

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