Question

How do you graph `(x-2)^2 + (y+1)^2 = 13`?

Answer 1

Explained below

Explanation:

The given equation represents a circle centered at (2, -1) and radius equal to `sqrt13`. First locate the point (2, -1) on the graph and the next task is to measure a radius equal to `sqrt13`. For this draw a right triangle with sides 12 and 5 units. Then with radius equal to the hypotenuse draw the required circle using (2, -1) as the center using compass.