How do you differentiate #y=-5^(4x^3)#?

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Answer 1 · 2016-01-30T07:47:18

you have to use chain rule to differentiate this function. this is how you do it,

#(dy)/(dx)#
#=d/(dx)(-5^(4x^3))#

#=-d/(dx)(5^(4x^3))#

suppose, a=5 so,

#-d/(dx)(5^(4x^3))#

#=-5^(4x^3)ln5d/(dx)(4x^3)#[as, #d/(dx)(a^x)=a^xlna#]

#=-5^(4x^3)ln5*4*3x^2#

#=-12*5^(4x^3)x^2ln5#