How do you differentiate #y = 2 / [3sqrt(x^2 - 5x)] #?

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Answer 1 · 2016-01-30T10:09:45

#(4x-10)/(3sqrt((x^2-5x)^3))#

Here,
#y=2/(3sqrt(x^2-5x))#

so,
#(dy)/(dx)#

#=d/(dx)(2/(3sqrt(x^2-5x)))#

#=2/3d/(dx)(1/(sqrt(x^2-5x)))#

#=2/3*1/((x^2-5x)^(3/2))d/(dx)(x^2-5x)#

#=2/3*1/((x^2-5x)^(3/2))(2x-5)#

#=(4x-10)/(3sqrt((x^2-5x)^3))#