Question

How do you differentiate `f(x) =arcsec(2x + 1)`?

Answer 1

`f'(x)=2/((2x+1)sqrt((2x+1)^2-1)`

Explanation:

Use the rule : `d/dxsec^(-1)u(x)=1/(usqrt(u^2-1))*(du)/dx`

`therefore d/dxsec^(-1)(2x+1)=2/((2x+1)sqrt((2x+1)^2-1)`