Question

How do you solve `3x+2y= -19` & `x-12y=19`?

Answer 1

X=-5 y=-2

Explanation:

Here,
`3x+2y=-19. . . . . .(1)`
`x-12y=19. . . . . . .(2)`

now, lets multiply equation (2) by 3 and substract from (1),
`(1)-3xx(2)=>`
`cancel(3x)+2y=-19`
`cancel(3x)-36y=57`
`_ _ _ _ _ _`
`38y=-76`
`or,y=-2`

now, by putting the value y=-2 in equation (1) we find,
`3x+2(-2)=-19`
`or,3x-4=-19`
`or,3x=-15`
`or,x=-5`
so, x=-2, y=-5