Question

How do you evaluate `sin(11(pi)/2)`?

Answer 1

Explanation is given below

Explanation:

`sin((11pi)/2)`
`=sin(6pi-pi/2)`

Note `color(magenta)(sin(2npi - theta) = -sin(theta)`
and `color(magenta)(sin(2npi + theta) = sin(theta)`

`=-sin(pi/2)`
`=-1`