Question

How do you convert `y=(x-y)^2-xy` into a polar equation?

Answer 1

here is how,

Explanation:

here,
`y=(x-y)^2-xy`

`or,y=x^2-2xy+y^2-xy`

`or,rsintheta=(x^2+y^2)-3xy`

`or,rsintheta=r^2-3rcosthetarsintheta`

`or,2rsintheta=2r^2-3*r^2*2costhetasintheta`

`or,2sintheta=2r-3rsin2theta`