Question

How do you find the equation of a circle with center at (-6, 2), passing through the point (-3,6)?

Answer 1

`(x+6)^2+(y-2)^2=25`

Explanation:

The line segment from the point `(-6,2)` to the point `(-3,6)` is a radius of the said circle. We can find the length of the radius using Pythagoras Theorem.

`r = sqrt{(-6-(-3))^2 + (2-6)^2}`

`= sqrt{9+16}`
`= 5`

Equation of circle:

`(x+6)^2+(y-2)^2=5^2`