How do you solve #5x+7=27#?

2 Answers
Feb 3, 2016

#5x+7=27#

#rarr5x=27-7#

#rarr5x=20#

#rarrx=20/5=4#

Feb 3, 2016

Subtract #7# from both sides of the equation
then divide both sides by #5# to isolate #x#
giving #x=4#

Explanation:

If
#color(white)("XXX")5x+7 = 27#
then
#color(white)("XXX")5x+7color(red)(-7)=27color(red)(-7)#
which simplifies as
#color(white)("XXX")5x=20#

If
#color(white)("XXX")5x=20#
then
#color(white)("XXX")(5x)color(red)(div5) = 20color(red)(div5)#
which simplifies as
#color(white)("XXX")x=4#