Question

How much work would it take to push a `2 kg` weight up a `2 m` plane that is at an incline of `pi / 3`?

Answer 1

The work done is given by `W=F*S*sin(theta)` where

`F=m*g` , `S=2m` , `theta=pi/3` so we have that

`W=m*g*S*sin(pi/3)=2*9.81*2*sin(pi/3)=33.98J`