How do you solve (x-4)(x+3) = 6?
1 Answer
Feb 5, 2016
Explanation:
How to solve
Step 1: Multiple the expand and combine like terms for the left side of the equation
(x^2-4x+3x-12)= 6
(x^2-x+-2) = 6
Step 2-Set the equation equal to zero by subtracting both side of the equation by 6
x^2 -x-12= 6
-6 " " " -6
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color(red)(x^2 -x -18= 0
Step 3 Solve the equation using quadratic formula, since we can't factor it
Recall: Quadratic formula:
color(red)(x^2 -x -18= 0
Substitute into the quadratic formula, we get
x= (1+-sqrt(1+72))/(2)
x= (1+-sqrt(73))/2