Question

If the length of a `29 cm` spring increases to `61 cm` when a `6 kg` weight is hanging from it, what is the spring's constant?

Answer 1

k = 6xx9.81/(32/100) = 6xx981/32 = 184 N/m#

Explanation:

See the free body diagram on the image, at equilibrium (0 acceleration) we have :
`sumF = F_k - mg = kDeltax - mg = 0`
`k = mg/(Deltax)`
You are given `m = 6kg; x_i = 29; x_f = 61`
`Deltax = x_f - x_i = 61 - 29 = 32 cm = 32/100`
`k = 6xx9.81/(32/100) = 6xx981/32 = 184 N/m`