Question

How do you find the roots, real and imaginary, of `y= x^2 -3x +7` using the quadratic formula?

Answer 1

the quadratic formula is:
`x_(1,2) = (-b+-sqrt(b^2-4ac))/(2a)`
`a= 1; b=-3; c=7`
If `sqrt(b^2-2ac)<0` then you have an imaginary number.
Now Substitute and you're home free...