Is #f(x)=-2x^3-2x^2+8x-1# concave or convex at #x=3#?

1 Answer
Feb 8, 2016

Concave (sometimes called "concave down")

Explanation:

Concavity and convexity are determined by the sign of the second derivative of a function:

  • If #f''(3)<0#, then #f(x)# is concave at #x=3#.
  • If #f''(3)>0#, then #f(x)# is convex at #x=3#.

To find the function's second derivative, use the power rule repeatedly.

#f(x)=-2x^3-2x^2+8x-1#

#f'(x)=-6x^2-4x+8#

#f''(x)=-12x-4#

The value of the second derivative at #x=3# is

#f''(3)=-12(3)-4=-40#

Since this is #<0#, the function is concave at #x=3#:

These are the general shapes of concavity (and convexity):

borisv.lk.net

We can check the graph of the original function at #x=3#:

graph{-2x^3-2x^2+8x-1 [-4,4, -150, 40]}