How do you graph #4x^2 + 4y^2 + 24x + 56 = 24y#?

1 Answer
Feb 9, 2016

First rearrange the terms to get all the #x# terms together and all the #y# terms together, then complete the squares to get the expression into the standard form of an ellipse or circle.

#4x^2 +24x +4y^2 -24y +56 = 0#
#4(x^2 +6x +y^2 -6y +14)=0#

We can divide the whole expression by #4# without affecting the final result.

#(x+3)^2 -9 +(y-3)^2 - 9 +14=0#
#(x+3)^2 +(y-3)^2 -4=0#
#(x+3)^2 +(y-3)^2 = 4#

This is now a circle with centre #(-3,3)# and radius #2# and can be graphed as such.