How do you find the determinant of #((-9, -7), (4, 5))#?
1 Answer
Feb 9, 2016
The determinant is
Explanation:
For a
#A = ( (a, b), (c, d)) # ,
the determinant can be computed as
#|A| = a * d - b * c#
Thus, in your example,
#abs( ( (-9, -7), (4, 5) ) ) = -9 * 5 - (-7)* 4 = -45 + 28 = -17#
