How do you solve #8^(0.2x) = 98.6#?

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Answer 1 · 2016-02-10T21:13:45

#x=ln(98.6)/(0.2*ln(8))~~11.03919#

You have to apply logarithms

the logarithm of #a^b# is #b ln(a)#

So:

#8^(0.2x)=98.6#

After aplying logarithms we have:

#0.2xln(8)=ln(98.6)#

#x=ln(98.6)/(0.2*ln(8))~~11.03919#