Question

If `32 L` of a gas at room temperature exerts a pressure of `72 kPa` on its container, what pressure will the gas exert if the container's volume changes to `16 L`?

Answer 1

`P_2=144 k Pa`

Explanation:

`P_1*V_1=P_2*V_2`
`72*cancel(32)=P_2*cancel(16)`
`72*2=P_2`
`P_2=144 k Pa`