How do you prove #Cos(x-(3pi)/2)=-sinx#?

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Answer 1 · 2016-02-12T01:58:33

Using the identities

We have:

#cos(x-(3pi)/2) = cos((x-pi)-pi/2)#

#=sin(x-pi)#

#=sin((x-pi/2)-pi/2)#

#=-cos(x-pi/2)#

#=-sin(x)#