How do you solve #12 - 4 x = 16#?

Question

1540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-14T11:02:52

#x=-1#

#12-4x=16#

Subtract #12# both sides:

#rarr-4x=16-12#

#rarr-4x=4#

Divide both sides by #4#

#rarr(-cancel4x)/cancel4=cancel4/cancel4#

#rarr-x=1#

#rArrx=-1#