Question

How do you solve `3/4x + 11 = 20`?

Answer 1

`x= 12`

Explanation:

First, get all the numbers to one side and the variable, x, to the other by subtracting 11 from both sides.

`3/4x +11=20`
`3/4x= 9`

Multiple both sides of the reciprocal of the coefficient (the number in front of the variable) to get x. The reciprocal for a fraction can be obtained by flipping the denominator and the numerator. For example, the reciprocal of the fraction `2/5` is `5/2`.

In this case, the coefficient is `3/4`, so its reciprocal would be `4/3`. Multiple both sides by `4/3` to cancel out the coefficient and find the value of x.

`(4/3)(3/4)x= 9(4/3)`

`x=12`

Answer 2

`x=12`

Explanation:

`3/4 x+11=20`

Subtract both sides by `11`:

`3/4 x=20-11`

`3/4 x=9`

Divide both sides by `3/4`

`x=9-:3/4`

`x=9*4/3`

`x=cancel9*4/cancel3`

`x=3*4=12`