Question

How do you normalize `( i - 2 j + 3 k )`?

Answer 1

Please check the explanation below.

Explanation:

A vector is normalised by dividing that with its magnitude. Suppose if `\vec{A_{}} = A_x\hat{i}+A_y\hat{j}+A_z\hat{k}` is the vector, its magnitude `A = |\vec{A_{}}| = \sqrt{A_x^2+A_y^2+A_z^2}`.

So the normalised vector is `\hat{A} = \vec{A_{}}/A=A_x/A\hat{i}+A_y/A\hat{j}+A_z/A\hat{k}`.