Question

If `14/3 L` of a gas at room temperature exerts a pressure of `45 kPa` on its container, what pressure will the gas exert if the container's volume changes to `13/5 L`?

Answer 1

`1050/13 ~~80.77 kPa`

Explanation:

Assuming the temperature remains constant, this is an application of Boyle's Law, which states that `P*V` (pressure times Volume) remains constant at constant temperature.
So, if

`V_1 = 14/3` and `P_1 = 45`

and `V_2 = 13/5` then since

`P_1*V_1 = P_2 *V_2`

`14/3*45 = P_2*13/5`

`(14*45*5)/(3*13) = P_2`

`P_2 = 1050/13 ~~80.77kPa`