Question

If `3/7 L` of a gas at room temperature exerts a pressure of `12 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5/9 L`?

Answer 1

`P_2~=9,26 k Pa`

Explanation:

`P_1*V_1=P_2*V_2`
`12*3/7=P_2*5/9`
`36/7=P_2*5/9`
`P_2=(36*9)/(5*7)`
`P_2~=9,26 k Pa`