The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #250 ^o C#. If the temperature of the gas changes to #200 ^oK# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-02-17T20:02:53

#P_2~=4,589 Pa#

#P_1/T_1=P_2/T_2#
#250^o C=273+250=523 ^o K#
#12/523=P_2/200#
#P_2=(200*12)/523#
#P_2~=4,589 Pa#