Question

If `14/3 L` of a gas at room temperature exerts a pressure of `21 kPa` on its container, what pressure will the gas exert if the container's volume changes to `13/7 L`?

Answer 1

`P_2=52,769 k Pa`

Explanation:

`P_1*V_1=P_2*V_2`
`14/cancel(3)*cancel(21)=13/7*P_2`
`P_2=14*7^2/13`
`P_2=52,769 k Pa`