How do you prove #(1+tan x) / (1+cot x) = 2#?

1 Answer
Feb 19, 2016

It is not an identity and thus, it can't be proven.

Explanation:

You can't prove it since it's not an identity.

Let's transform the left side using

#tan x = sin x / cos x#, #" " cot x = cos x / sin x #

We have

#(1 + tan x ) / (1 + cot x ) = (1 + sin x / cos x) / (1 + cos x / sin x)#

# = (cos x/ cos x + sin x / cos x) / (sin x / sin x + cos x / sin x)#

# = ( (cos x + sin x) / cos x) / ( (sin x + cos x) / sin x)#

# = (cos x + sin x) / cos x * sin x / (sin x + cos x) #

# = (cancel((cos x + sin x)) * sin x) / (cos x * (cancel(sin x + cos x))) #

# = sin x / cos x #

# = tan x #

However, #tan x = 2# is certainly not true for all #x#.

Thus, your equation is not an identity and can't be proven.