Question

What are the mean and standard deviation of a binomial probability distribution with `n=94` and `p=32/37`?

Answer 1

Mean is `81.297` and standard deviation is `3.315`

Explanation:

Mean of a binomial probability distribution is given by `np` and standard deviation is given by `sqrtnpq`, where `q=1-p`.

In the given example, `np=94*32/37=81.297`,

As `q=1-32/37=5/37`, `sqrtnpq=sqrt(94*32/37*5/37)=4/37*sqrt940=3.315`

Hence mean is `81.297` and standard deviation is `3.315`