The gas inside of a container exerts $5 Pa$ of pressure and is at a temperature of $120 ^o C$ . If the temperature of the gas changes to $180 ^oK$ with no change in the container's volume, what is the new pressure of the gas?

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The gas inside of a container exerts $5 Pa$ of pressure and is at a temperature of $120 ^o C$ . If the temperature of the gas changes to $180 ^oK$ with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-02-21T14:48:48

$P_2~=2,29 Pa$

Explanation:

$"we can use the Gay-Lussac's law"$
$P_1/T_1=P_'/T_2$
$"change "120 ^o C " to " ^o K" 120+273=393 ^o K$
$5/393=P_2/180$
$P_2=(180*5)/393$
$P_2~=2,29 Pa$

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The gas inside of a container exerts $5 Pa$ of pressure and is at a temperature of $120 ^o C$ . If the temperature of the gas changes to $180 ^oK$ with no change in the container's volume, what is the new pressure of the gas?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

The gas inside of a container exerts 5 Pa5 Pa of pressure and is at a temperature of 120 ^o C120 ^o C. If the temperature of the gas changes to 180 ^oK180 ^oK with no change in the container's volume, what is the new pressure of the gas?

1 Answer

Explanation:

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The gas inside of a container exerts $5 Pa$ of pressure and is at a temperature of $120 ^o C$ . If the temperature of the gas changes to $180 ^oK$ with no change in the container's volume, what is the new pressure of the gas?