The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #450 ^o K#. If the temperature of the gas changes to #90 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-02-22T09:32:05

#P_2=12,1 Pa#

#" we can use the Gay-Lussac's Law to solve this problem"#
#P_1/T_1=P_2/T_2#
#15/450=P_2/(273+90)#
#15/450=P_2/363#
#P_2=(15*363)/450#
#P_2=12,1 Pa#