Question

If 69.5 kJ of heat is applied to a 1012-g block of metal, the temperature of the metal increases by 11.4°C. What is the specific heat capacity of the metal in J/g°C?

Answer 1

`=6.024J//g.^@C`

Explanation:

`W=mcDeltaT`

`therefore c= W/(mDeltaT)`

`=(69500J)/((1012g)(11.4^@C)`

`=6.024J//g.^@C`.

(Note that the SI unit of specific heat capacity is actually `J//kg.K`).