Question

What are the mean and standard deviation of a binomial probability distribution with n=13 and p=0.1?

Answer 1

Mean is `1.3` and standard deviation is `1.08`.

Explanation:

As mean is given by `n*p`, it is `13*0.1=1.3`.

Standard Deviation is given by`sqrt(npq)`, where `q=1-p`. Hence `q=0.9` and

Standard Deviation is `sqrt(13*0.1*0.9)=sqrt1.17=1.08`