Question

A container with a volume of `16 L` contains a gas with a temperature of `210^o K`. If the temperature of the gas changes to `420 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

The new volume is `32L`

Explanation:

According to the Gas Equation we can write that `(p*V)/T=const`

So now we know that the pressure `p` does not change, so only temperaturw `(T)` and volume`(V)` changes

`(p*V_1)/T_1=(p*V_2)/T_2`

if we divide by `p` we have `V_1/T_1=V_2/T_2`

`V_2=(V_1*T_2)/T_1`

`V_2=(16*420)/210`

`V_2=32L`