What is the center and radius of the circle with equation #x^2 + (y + 6)^2 = 49#?

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Answer 1 · 2016-02-26T01:25:01

Center #(0, -6)# and Radius#=7#

We can transform first to the center-radius form first for proper visibility

#x^2+(y+6)^2=49#

#(x-0)^2+(y--6)^2=7^2#
now it takes the form
#(x-h)^2+(y-k)^2=r^2#

so that, just by inspection, it is now clear that

Center #(0, -6)# and Radius#=7#

graph{(x-0)^2+(y--6)^2=7^2[-20,20,-18,2]}

God bless...I hope the explanation is useful...